### All ISEE Middle Level Quantitative Resources

## Example Questions

### Example Question #61 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 87 is the multiplier and 86 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 6

Then, we multiply 7 and 8 and add the 4 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 8 and 6

Then, we multiply 8 and 8and add the 4 that was carried

Finally, we add the two products together to find our final answer

### Example Question #62 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 52 is the multiplier and 40 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 0

Then, we multiply 2 and 4

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 5 and 0

Then, we multiply 5 and 4

Finally, we add the two products together to find our final answer

### Example Question #63 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 13 is the multiplier and 32 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 2

Then, we multiply 3 and 3

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 1 and 2

Then, we multiply 1 and 3

Finally, we add the two products together to find our final answer

### Example Question #64 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 62 is the multiplier and 37 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 7

Then, we multiply 2 and 3 and add the 1 that was carried

Next, we multiply 6 and 7

Then, we multiply 6 and 3and add the 4 that was carried

Finally, we add the two products together to find our final answer

### Example Question #65 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 28 is the multiplier and 88 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 8

Then, we multiply 8 and 8 and add the 6 that was carried

Next, we multiply 2 and 8

Then, we multiply 2 and 8and add the 1 that was carried

Finally, we add the two products together to find our final answer

### Example Question #66 : Whole Numbers

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 54 is the multiplier and 45 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 5

Then, we multiply 4 and 4 and add the 2 that was carried

Next, we multiply 5 and 5

Then, we multiply 5 and 4and add the 2 that was carried

Finally, we add the two products together to find our final answer

### Example Question #1031 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 12 is the multiplier and 81 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 1

Then, we multiply 2 and 8

Next, we multiply 1 and 1

Then, we multiply 1 and 8

Finally, we add the two products together to find our final answer

### Example Question #1032 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 56 is the multiplier and 34 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 4

Then, we multiply 6 and 3 and add the 2 that was carried

Next, we multiply 5 and 4

Then, we multiply 5 and 3and add the 2 that was carried

Finally, we add the two products together to find our final answer

### Example Question #1033 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 55 is the multiplier and 64 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 4

Then, we multiply 5 and 6 and add the 2 that was carried

Next, we multiply 5 and 4

Then, we multiply 5 and 6and add the 2 that was carried

Finally, we add the two products together to find our final answer

### Example Question #1034 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Solve:

**Possible Answers:**

**Correct answer:**

For this problem, 52 is the multiplier and 85 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 2 and 5

Then, we multiply 2 and 8 and add the 1 that was carried

Next, we multiply 5 and 5

Then, we multiply 5 and 8and add the 2 that was carried

Finally, we add the two products together to find our final answer

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